Various preliminary considerations are first required in dimensioning a Roots pumping station.
Compression ratio
The compression ratio
of a Roots pump is typically between 5 and 70. To determine this ratio, we first consider the volume of gas pumped and the backflow by means of conductivity
, as well as the return flow of gas from the discharge chamber at pumping speed
:
Formula 2-1: Roots pump gas load
S 체적 유량율(펌프 속도)
S0 유입 측면의 이론적 펌프 속도
SR 반환 기체 흐름의 펌프 속도
CR 전도성
pa 유입구 압력
pv 배압 진공 압력
S를 0과 동일하다고 선택하면 다음과 같은 압축비를 구할 수 있습니다.
Formula 2-2: Compression ratio of Roots pump
K0 Compression ratio
In the case of laminar flow the conductance is significantly greater than the pumping speed of the backflow. This simplifies Formula 2-2 to
Formula 2-3: Compression ratio of Roots pump for laminar flow
In the molecular flow range, the pumping speed is still greatest on the intake side, but the pumping speed of the backflow is now considerably greater than the conductance. The compression ratio is therefore:
Formula 2-4: Compression ratio of Roots pump for molecular flow
At laminar flow (high pressure), the compression ratio is limited by backflow through the gap between the roots lobes and the housing. Since conductance is proportional to mean pressure, the compression ratio will decrease as pressure rises.
In the molecular flow range, the return gas flow SR⋅pv from the discharge side predominates and limits the compression ratio toward low pressure. Because of this effect, the use of Roots pumps is restricted to pressures pa of more than 10-4 hPa.
Pumping speed
Roots pumps are equipped with overflow valves that allow maximum pressure differentials Δpd of between 30 and 60 hPa at the pumps. If a Roots pump is combined with a backing pump, a distinction must be made between pressure ranges with the overflow valve open (S1) and closed (S2).
Since gas throughput is the same in both pumps (Roots pump and backing pump), the following applies:
Formula 2-5: Pumping speed of Roots pumping station with overflow valve open and at high fore-vacuum pressure
S1 Pumping speed with overflow valve open
SV Pumping speed of backing pump
pv Fore-vacuum pressure
Δpd maximum pressure differential between the pressure and intake side of the Roots pump
As long as the pressure differential is significantly smaller than the fore-vacuum pressure, the pumping speed of the pumping station will be only slightly higher than that of the backing pump. As backing vacuum pressure nears pressure differential, the overflow valve will close and will apply
Formula 2-6: Pumping speed of Roots pumping station with overflow valve closed and fore-vacuum pressure close to differential pressure
Let us now consider the special case of a Roots pump working against constant pressure (e. g. condenser mode). Formula 2-3 will apply in the high pressure range. Using the value CR in Formula 1 and disregarding the backflow SR against the conductance value CR we obtain:
Formula 2-7: Pumping speed of Roots pumping station at high intake pressure
At low pressures, SR from Formula 2-4 is used and we obtain
Formula 2-8: Pumping speed of Roots pumping station at low intake pressure
From Formula 2-6 , it can be seen that S tends toward S0 if the compression ratio K0 is significantly greater than the ratio between the theoretical pumping speed of the Roots pump S0 and the fore-vacuum pumping speed SV.
Selecting the compression ratio, for example, as equal to 40 and the pumping speed of the Roots pump as 10 times greater than that of the backing pump, then we obtain S = 0.816 ⋅S0
For the purposes of adjustment for use in a pumping station the theoretical pumping speed of the Roots pump should therefore not be more than ten times greater than the pumping speed of the backing pump.
Since the overflow valves are set to pressure differentials of around 50 hPa, virtually only the volume flow rate of the backing pump is effective for pressures of over 50 hPa. If large vessels are to be evacuated to 100 hPa within a given period of time, for example, an appropriately large backing pump must be selected.
Let us consider the example of a pumping station that should evacuate a vessel with a volume of 2 m³ to a pressure of 5 · 10-3 hPa in 10 minutes. To do this, we would select a backing pump that can evacuate the vessel to 50 hPa in 5 minutes. The following applies at a constant volume flow rate:
Formula 2-9: Pump-down time
t1 Pump-down time of backing pump
V Volume of vessel
S Pumping speed of backing pump
p0 Initial pressurep1Final pressure
By rearranging Formula 2-9, we can calculate the required pumping speed:
Formula 2-10: Calculating the pumping speed
Using the numerical values given above we obtain:
We select a Hepta 100 with a pumping speed 𝑆𝑉 = 100 m³ h-1 as the backing pump. Using the same formula, we estimate that the pumping speed of the Roots pump will be 61 l s-1 = 220 m³ h-1, and select an Okta 500 with a pumping speed 𝑆0 = 490 m³ h-1 and an overflow valve pressure differential of Δ𝑝𝑑 = 53 hPa for the medium vacuum range.
From the table below, we select the fore-vacuum pressures given in the column 𝑝𝑣, use the corresponding pumping speeds 𝑆𝑉 for the Hepta 100 from its pumping speed curve and calculate the throughput: 𝑄=𝑆𝑉⋅𝑝𝑣.
The compression ratio
is calculated for an open overflow valve up to a fore- vacuum pressure of 56 hPa. K0 for fore-vacuum pressures ≤ 153 hPa is taken from Figure 2.1. There are two ways to calculate the pumping speed of the Roots pump:
S1 can be obtained from Formula 2-5 for an open overflow valve, or S2 on the basis of Formula 2-6 for a closed overflow valve.
As the fore-vacuum pressure nears pressure differential Δpd,S1 will be greater than S2. The lesser of the two pumping speeds will always be the correct one, which we will designate as S. The inlet pressure is obtained with the formula:
Figure 2.2 shows the pumping speed graph for this pumping station.
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Figure 2.1: No-load compression ratio for air with Roots pumps
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Figure 2.2: Volume flow rate (pumping speed) of a pumping station with Hepta 100 and Okta 500
Pa / hPa | Pv / hPa | Sv / (m3 / h) | Q / (hPa · m3/ h) | KΔ | K0 | S1 / (m3 / h) | S2 / (m3 / h) | t / h | t / s |
1,000.0000 | 1,053.00 | 90.00 | 94,770.00 | 1.05 | 94.77 | 0.00490 | 17.66 | ||
800.0000 | 853.00 | 92.00 | 78,476.00 | 1.07 | 98.10 | 0.00612 | 22.04 | ||
600.0000 | 653.00 | 96.00 | 62,688.00 | 1.09 | 104.48 | 0.00827 | 29.79 | ||
400.0000 | 453.00 | 100.00 | 45,300.00 | 1.13 | 113.25 | 0.01359 | 48.93 | ||
200.0000 | 253.00 | 104.00 | 26,312.00 | 1.27 | 131.56 | 0.00652 | 23.45 | ||
100.0000 | 153.00 | 105.00 | 16,065.00 | 1.53 | 7.00 | 160.65 | 321.56 | 0.00394 | 14.18 |
50.0000 | 103.00 | 105.00 | 10,815.00 | 2.06 | 13.00 | 216.30 | 382.20 | 0.00608 | 21.87 |
14.9841 | 56.00 | 110.00 | 6,160.00 | 18.70 | 18.00 | 2,053.33 | 411.10 | 0.00822 | 29.58 |
2.5595 | 10.00 | 115.00 | 1,150.00 | 36.00 | 449.30 | 0.01064 | 38.30 | ||
0.2300 | 1.00 | 105.00 | 105.00 | 50.00 | 456.52 | 0.00670 | 24.13 | ||
0.0514 | 0.30 | 75.00 | 22.50 | 46.00 | 437.39 | 0.00813 | 29.27 | ||
0.0099 | 0.10 | 37.00 | 3.70 | 40.00 | 375.17 | 0.00673 | 24.23 | ||
0.0033 | 0.06 | 15.00 | 0.90 | 39.00 | 270.42 | 0.00597 | 21.51 | ||
0.0018 | 0.05 | 5.00 | 0.25 | 37.00 | 135.29 | ||||
Pump-down time: 344.94 s | |||||||||
Table 2.1: Pumping speed of a Roots pumping station and pump-down times
Pump-down times
The pump-down time for the vessel is calculated in individual steps. In areas with a strong change in pumping speed, the fore-vacuum pressure intervals must be configured close together. Formula 2-9 is used to determine the pump-down time during an interval, with S being used as the mean value of the two pumping speeds for the calculated pressure interval. The total pump-down time will be the sum of all times in the last column of Table 2-1.
The pump-down time will additionally be influenced by the leakage rate of the vacuum system, the conductances of the piping and of vaporizing liquids that are present in the vacuum chamber, as well as by degassing of porous materials and contaminated walls. Some of these factors will be discussed in Sections 2.2.3.1 and 2.3. If any of the above-mentioned influences are unknown, it will be necessary to provide appropriate reserves in the pumping station.
